00:01
For this problem on the topic of relativity, we want to suppose that the speed of flight was 65 miles an hour, your workplace was 30 miles from your home, and a typical driving speed would be 60 miles an hour.
00:12
Now, if you were to drive at that speed for a round trip to and from work, we want to know how by how much your wristwatch would lag your kitchen clock each day.
00:22
We then want to estimate the length of the car, and we want to know how long the car would be when viewed from the roadside.
00:30
We want to know then what would be the speed relative to you of similar cars traveling toward you in the opposite lane with the same ground speed as you and how long you would measure those cars to be.
00:42
If a total mass of you in the car was 2 ,000 kilograms, we want to know the work that would be required to get you up to that speed.
00:49
And lastly, how much work would be required in the real world where the speed of light is three times 10 to the 8 meters per second to get you up to speed.
00:58
Now we want the time difference between the kitchen clock and the moving wristwatch for the first part of problem a.
01:05
And so for the kitchen clock time, we drive at 60 miles, we drive 60 miles at 60 miles an hour.
01:14
And so the time would be one hour.
01:18
But measured by your wristwatch, the time is the proper time where delta t is gamma delta t -naut.
01:31
And gamma is equal to 1 over the square root of 1 minus u squared over c squared, which is 1 over the square root of 1 minus 60 over 65 squared, which gives 0 .0 .n's factor of 2 .6.
01:58
And so the time measured by the watch delta t -0 is delta t over gamma, which is one hour divided by 2 .6, which is 0 .38 of an hour, which is 23 minutes.
02:23
So the wristwatch would measure a time of 23 minutes.
02:26
Now for part b, the estimate of the length of the car would be 15 feet in length.
02:47
And for part c, we want its length l from a roadside observer, and this will be its proper length, l0, which is equal to 15 feet...