00:02
We have the beer lambert law.
00:07
And here, this would be log base 10 of the intensity of light after passing through that length of liquid divided by i .0.
00:22
This would be the incident intensity.
00:24
This is going to be equalling to negative epsilon, the extinction coefficient, multiplied by the concentration of the absorbing molecules in the fluid, multiplied by l the length of the fluid.
00:37
And so for 660 nanometer light, the absorbing molecules are going to be oxygenated hemoglobin.
00:45
And so we can say that if only 33 % of this wavelength light is transmitted through the blood, then we can say that the concentration of oxygenated hemoglobin in the blood is going to be c, sub hbo, 2, this is going to be equalling negative log 10, log base 10 of 0 .33.
01:15
Again, 33 % of this wavelength, light is transmitted through this blood, divided by the extinction coefficient times l, the length.
01:26
And so we have, for the absorbing molecules for 940 nanometer light, are deoxygenated hemoglobin.
01:37
So here, if 76 % of this light is transmitted to the blood, this means that the concentration of these molecules in the blood, this would be for the, again, the deoxygenated hemoglobin.
01:55
Negative log base 10 .76 divided by the extinction coefficient times l, the length.
02:07
Now we're going to divide these two equations and say c sub hb...