00:01
In the first part of this problem, we are going to calculate the charge on the capacitor.
00:06
But the charge on the capacitor is denoted by this capital clone.
00:10
In order to calculate this charge, let's supply the low of conservation of energy.
00:14
For which you can write, this uc is equal to ul.
00:19
So uc is the maximum energy stored in the capacitor, and this ul is the maximum energy stored in the inductor.
00:26
Now, this can be written as 1 divided by 2, capital q squared divided by c is equal.
00:31
Equals to 1 divided by 2 capital l i not square here this i not square i not is the maximum current in the circuit and this l is the indictance while this c is the capacitance of the capacitor now this can be written for the capital q as capital q is equals to i 0 square root of l multiply by c let's call it equation number one let's put the values into this equation so this can be written as capital q is equals to 0 0 .750 ampere into square root of this l which is the value of 80 .0 multiplied 10 raise power minus 3 amrruy into the value of c which is equal to 1 .25 multiplied 10 x bar minus 9 ferret and we have the square root up to this point.
01:27
From here we can write the value for this capital q as capital q is equal to 7.
01:34
Multiple by 10x bar minus 6 cooler or it can be written as 7 .50 micro pull up.
01:42
So this is the answer to the first part of this problem...