$$\operatorname{erf} x=\frac{2}{\sqrt{\pi}} \int_{0}^{x} e^{-x^{2}} d w$$
This function is important in applied mathematics and physics (probability theory and statistics, thermodynamics, etc.) and fits our present discussion. Regarding it as a typical case of a special function defined by an integral that cannot be evaluated es in elementary calculus, do the following.
(a) Sketch or graph the bell-shaped curve [the curve of the integrand in (21) ). Show that erf $x$ is odd. Show that
$$\begin{array}{c}
\int_{a}^{b} e^{-w^{a}} d w=\frac{\sqrt{\pi}}{2}(\operatorname{crf} b-\cos a) \\
\int_{-b}^{b} e^{-x^{2}} d w=\sqrt{\pi} \operatorname{erf} b
\end{array}$$
(b) Obtain the Maciaurin series of erf $x$ from that of the integrand. Use that series to compute a table of erf $x$ for $x=0(0,01) 3$ (meaning $x=0,0.01,0.02$
$\cdots \times 3$)
(c) Obtain the values required in (b) by an integration command of your CAS. Compare accuracy.
(d) It can be shown that erf $(\infty)=1 .$ Confirm this experimentally by computing erf $x$ for large $x$
(e) Let $f(x)=1$ when $x>0$ and 0 when $x<0 .$ Using erf $(\infty)=1,$ show that (12) then gives
$$\begin{aligned}
u(x, t) &=\frac{1}{\sqrt{\pi}} \int_{-\pi t 2 \epsilon \sqrt{t}} e^{-x^{2}} d z \\
&=\frac{1}{2}-\frac{1}{2} \operatorname{erf}\left(-\frac{x}{2 c \sqrt{t}}\right) \quad(t>0)
\end{aligned}$$
(f) Express the temperature (13) in terms of the error function
$$\begin{aligned}
&\text { (g) Show that } \Phi(x)=\frac{1}{\sqrt{2 \pi}} \int_{-\infty}^{\infty} e^{-s^{2} \pi k} d s\\
&=\frac{1}{2}+\frac{1}{2} \operatorname{erf}\left(\frac{x}{\sqrt{2}}\right)
\end{aligned}$$
Here, the integral is the definition of the "distribution function of the normal distribution" to be discussed in $\sec 24.8$