Question
$\operatorname{Let} \mathbf{X}=\left(\begin{array}{l}x \\ y\end{array}\right) .$ Then $\mathbf{X}^{\prime}=\left(\begin{array}{rr}4 & -7 \\ 5 & 0\end{array}\right) \mathbf{X}$
Step 1
First, let's find the product of the given matrix and the vector X: $\mathbf{X}^{\prime} = \left(\begin{array}{rr}4 & -7 \\ 5 & 0\end{array}\right) \left(\begin{array}{l}x \\ y\end{array}\right)$ Show more…
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