00:02
Okay, so in this problem we are asked to find the sublimation, the heat of sublimation for lithium.
00:10
And for solving this problem it's useful to look at the reaction of formation for the lithium iodide salt or solid.
00:20
So this is the reaction that we're going to use.
00:22
We start with solid lithium, we have iodine gas, and they will react to form the salt or the ionic solid, which is lithium iodide.
00:33
And we are also given the delta h or the enthalpy for the reaction, which is negative 272 kilojoules per mole.
00:42
So it is useful to think of this reaction as a series of steps that have to be accomplished to go from the reactants to the final product.
00:51
So let's look at what steps we need to accomplish for that.
00:55
The first thing that we need to do is turn that lithium solid into a gas.
01:00
Why? because the iodine is also in a gas phase, so they both need to be in the same phase, in the gas phase, for them to react.
01:08
And that first reaction, turning the lithium solid to the lithium gas, is basically the heat of sublimation that we are going for the problem, we're just going to represent by a delta h sub.
01:19
And this is actually the value that we need to find for the problem.
01:24
So we don't know the answer for this value right now.
01:26
The second step is we would have to take that lithium gas and ionize it, because remember that the final product is an ionic solid.
01:36
So we need to have a positive lithium ion and a negative iodide ion, an ion in this case, for them to merge and form the solid.
01:47
So we need to ionize that lithium gas neutral atom into a positive ion.
01:54
And that's basically the ionization energy for lithium, which is given by the problem.
02:01
And it's 520 kilojoules per mole.
02:05
This is the ionization energy for lithium.
02:09
The third step, or a separate step that we need to accomplish, is we need to turn that gas, which has a covalent bond, into a single iodine atom...