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.. Ordinary glasses. Ordinary glasses are worn in front of the eye and usually 2.0 $\mathrm{cm}$ in front of the eyeball. Suppose that the person in the previous problem prefers ordinary glasses to contact lenses. What focal length lenses are needed to correct his vision, and what is their power in diopters?

$+2.02$ diopters

Physics 102 Electricity and Magnetism

Physics 103

Chapter 25

Optical Instruments

Electromagnetic Waves

Reflection and Refraction of Light

Cornell University

University of Michigan - Ann Arbor

McMaster University

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Okay, So the question was asking us. Well, focal lens. I needed to correct his vision. And what is their power in deal porters? Okay, so first we know the equation you swallow over at people. So I were being small for you. If Mr Focal lands beast, the image distance and you just the object distance. So we it was just the image distance at this point. Well, if we said at a near point of view off the person is 45 7 year. That means that if a person want to see an object at 25 7 years for his eyes, an image off object must be at 45 minutes. Okay, so the distance between the lands and eyes is to send me. This is given from a question. OK, so the distance between the lands and object was its main. Since the object distance is able to 25 centimeters minds to seven years and he's equal to 23 centimeters. And the distance between the lands and image is equal to 45 centimeters minus two centimeter, which is 43 7 year. Okay, So 43 centimeter is the the image distance okay. And a most business. It's connected in this case, since it's for the conversion plants. OK, so if we plugging to the equations, we get it. Ah f You know, if we does, our regiment have can be equal to M. C. Should be UV over you, Percy. Okay, I'm replying. No value or get you, which is object distance turning three centimeter times. Negative. 43 7 years. Okay, because is negative. Fuller Commercially. Okay, So you class, will you be 23 centimeter plus negative 43 seven years and this will give us the focal lane is about 49 point will fly centimeters. It's now where the focal length So give you terming the full power, which is equal to P, is equal to one over half. We know AF is give as 49 0.45 centimetres. Okay, So the power, the focal power is equal to one over 49 point for fire times tend to a power naked too. Meter six. Want centimeters tense About negative two meter and this will give us the The heart is equal to 2.2 meter to power enacted. One, which is 2.2. The overtures. Okay, and in his case, it's easy to point to. So it's positive. So it's positive. 2.2 the openers and these are the solution for the question. Thank you.

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