Question
Oscillation of a 600 Hz tuning fork sets up standing waves in a string clamped at both ends. The wave speed for the string is400 $\mathrm{m} / \mathrm{s}$ . The standing wave has four loops and an amplitude of2.0 $\mathrm{mm}$ (a) What is the length of the string? (b) Write an equationfor the displacement of the string as a function of position and time.
Step 1
Each loop represents half a wavelength, so four loops represent two wavelengths. Therefore, the length of the string is equal to two wavelengths. We can write this as $L = 2\lambda$. Show more…
Show all steps
Your feedback will help us improve your experience
Ben Nicholson and 65 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Oscillation of a 600 Hz tuning fork sets up standing waves in a string clamped at both ends. The wave speed for the string is 400 $\mathrm{m} / \mathrm{s}$ . The standing wave has four loops and an amplitude of 2.0 $\mathrm{mm}$ (a) What is the length of the string? (b) Write an equation for the displacement of the string as a function of position and time.
Vibrations from a $622-\mathrm{Hz}$ tuning fork set up standing waves in a string clamped at both ends. The wave speed for the string is $388 \mathrm{~m} / \mathrm{s}$. The standing wave has four loops and an amplitude of $1.90 \mathrm{~mm} .$ (a) What is the length of the string? (b) Write an equation for the displacement of the string as a function of position and time.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD