00:01
Hi, in the given problem, we have some elkins, a, b, c, and d.
00:08
Out of these given elkins, we have to identify the one which exhibit optical isomerism.
00:13
We know that optical isomerism is shown by the compounds, chiral atoms.
00:39
So now we will look for the chiral atom in these ilkines and then identify the compound that shows optical isomerism.
00:48
Let us write the structure of these compounds and analyze.
00:51
The first structure is 3 methyl 2 -pentine, which can be written as ch3, ch double bond, c -bonded 2, ch3, ch2, ch3.
01:06
Now we can see here in this compound, there is no atom which is wanted to four different atoms of groups.
01:13
So there is no chiral carbon present in the first compound.
01:18
Compound and it does not show optical isomerism.
01:22
The second compound is 4 methyl 112 which can be written as ch2 double bond ch, ch2, ch2, ch bonded to ch3 and ch3.
01:37
Now in this case again we can see there is no carbon atom which is chiral so it does not exhibit optical isomerism.
01:49
Looking for that compound c we can write the structure c .h.
01:55
2 double bond.
01:57
C .h.
01:59
C .h.
02:00
Bonded to ch3...