00:05
This question asks us how we can synthesize each of these molecules from acetylene, which i've drawn up above.
00:11
So to start with letter a, if we take acetylene.
00:17
And all we're doing here is adding on this alkyl chain, which is three carbons.
00:22
So to do that with an alkyn, we will first start with sodium amid.
00:26
And that will take off one of these hs and make it a carbonyon.
00:32
And then we will add a chloroalkane with the desired number of carbon.
00:38
So here we want three carbons.
00:39
So we'll do one, two, three carbons with the chlorine.
00:44
And then that will give us our product.
00:48
For part b, we have a similar situation here where we need to add a carbon onto the end.
00:54
So we'll do that first.
00:56
So we'll start with that acetylene.
01:00
We'll do our sodium amid.
01:02
And then here we're only adding one carbon, so that'll just be ch3cl.
01:07
And we'll get that added onto the end.
01:10
But this is still an alkyne.
01:12
So now we need to take it from an alkyne to an alkyne.
01:17
So to do that, we'll use h2 with the lindlar catalyst.
01:23
And we have to use that one here instead of the sodium and liquid ammonia because only the linlar one works on terminal alkynes to turn them into alkenes.
01:34
And that will give us our product.
01:38
For part c, again, we're going to start by adding on some carbons.
01:41
So if we think about this one, we have some stuff going on on the end here, which means that the alkyne was between these last two carbons.
01:50
So we've added three carbons on.
01:52
So we'll start by doing that.
01:55
So again, we'll take our sodium amid.
01:58
And then here we have three carbons added on.
02:00
So we're one, two, three, chlorine...