Question
Owing to a faulty door contact, the small light bulb (25 W) inside a refrigerator is kept on and limited insulation lets $50 \mathrm{W}$ of energy from the outside seep into the refrigerated space. How much of a temperature difference to the ambient surroundings at $20^{\circ} \mathrm{C}$ must the refrigerator have in its heat exchanger with an area of $1 \mathrm{m}^{2}$ and an average heat transfer coefficient of $15 \mathrm{W} / \mathrm{m}^{2} \mathrm{K}$ to reject the leaks of energy?
Step 1
This is given by: \[E_{\text{total}} = E_{\text{bulb}} + E_{\text{seep}} = 25 \, \text{W} + 50 \, \text{W} = 75 \, \text{W}\] Show more…
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The black grille on the back of a refrigerator has a surface temperature of $35^{\circ} \mathrm{C}$ with a total surface area of $1 \mathrm{~m}^{2}$. Heat transfer to the room air at $20^{\circ} \mathrm{C}$takes place with an average convective heat transfer coefficient of $15 \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}$. How much energy can be removed during 15 minutes of operation?
The black grille on the back of a refrigerator has a surface temperature of $35^{\circ} \mathrm{C}$ with a total surface area of $1 \mathrm{m}^{2} .$ Heat transfer to the room air at $20^{\circ} \mathrm{C}$ takes place with an average convective heat transfer coefficient of $15 \mathrm{W} / \mathrm{m}^{2} \mathrm{K} .$ How much energy can be removed during 15 minutes of operation?
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