Oxygen gas reacts with powdered aluminum according to the following reaction:
$$
4 \mathrm{Al}(s)+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{Al}_{2} \mathrm{O}_{3}(s)
$$
What volume of $\mathrm{O}_{2}$ gas (in $\mathrm{L}$ ), measured at $782 \mathrm{mmHg}$ and $25^{\circ} \mathrm{C}$, is required to completely react with $53.2 \mathrm{~g}$ Al?