00:01
All right guys, the stoichiometric reaction and the corresponding coefficients are 02, then we've got v -o -2 is equal to 1 and v -o -o -2 is equal to 2.
00:22
So in this case the actual reaction can be written as this is part a.
00:33
In this case, the reaction can be written as a -o -2 plus a part a -2.
00:43
2 into 1 minus a .o.
00:49
The coefficient is determined from the equilibrium coefficient relation where the value of the coefficient is taken from table 828 and the given temperature that is e raised to power natural log kp is equal to n o, raised to power v o divided by n o 2 raised to power v o 2, by p over n raised to power v o minus v o two so guys e raised to power minus 4 .357 is equal to 2 2 into 1 minus a square divided by a multiplied by 1 divided by a plus 2 minus 2 a raised to power 2 minus 1, then we've got 4 .01 -282 raised to power a square minus 8 .02563a plus 4 is equal to 0 .94563a, then a is equal to 0 .945.
02:12
So the final form of the reaction is 0 .2, 0 .9435.
02:35
02 plus 0 .113 .0.
02:40
The rate of heat transfer is determined from the enthulpies of formation and the molar enthalpy at the given temperature taken from table a18 to 826.
02:51
So we've got q is equal to m over capital m into n into hf plus double dot bar plus h bar plus h.
03:07
Double dot bar minus n into hf double dot bar plus h bar minus h .d .d .b.
03:25
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