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Oxygen reaches the veinless cornea of the eye by diffusing through its tear layer, which is 0.500-mm thick. How long does it take the average oxygen molecule to do this?

$t=125 \mathrm{s}$

Physics 101 Mechanics

Chapter 12

Fluid Dynamics and Its Biological and Medical Applications

Fluid Mechanics

Cornell University

University of Washington

Simon Fraser University

Lectures

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so we know that the root mean distance square for a molecule, or the average distance that a molecule travels is going to be equal to a square root of two times the diffusion constant of that molecule in a certain medium. In this case, it would be, ah, the oxygen molecules through the tear layer times t the time and so finding time. This would be equaling. The root means square distance squared, divided by two times the diffusion constant. And we're going to say that the Time T would be equaling 20.500 times 10 to the negative third meter quantity squared, divided by two times the diffusion constant of 1.0 times 10 to the negative ninth meters squared per second. And so this is equaling 1.25 times 10 to the second seconds. This would be your final answer. And again, this is simply the time taken by the oxygen molecule to reach the vein lis cornea of the eye. And so this would be the time it takes to go through that tear layer 1.25 times, 10 to the second seconds. This would be our final answer. That is the end of the solution. Thank you for watching

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