00:01
So for this problem, we're given information about beth, bill, and edie and their house painting capabilities.
00:08
And we're asked to identify how long it would take each one of them to paint a house on their own, based on the ways they can paint houses interacting with each other.
00:23
So i'm going to assign a variable to each of these people.
00:27
Beth will be x.
00:28
Bill will be y and ed will be z.
00:33
I would use letters of their name, except that e is its own number when it's a variable.
00:39
And beth and bill both start with b.
00:41
So i'll use x, y, and z just to keep things clear, as that's pretty typical for systems of equations.
00:49
The other thing is what these variables represent.
00:52
So that variable is going to represent how many houses per per hour that individual can paint.
01:04
So we're looking at houses per hour.
01:08
And that's just their rate of painting houses.
01:12
And so we know that when we have all of them together and they're working for 10 hours, they complete one house.
01:22
So that's when beth is working for 10 hours, and bill is working for 10 hours.
01:29
And edie is working for 10 hours.
01:30
And edie is working for 10 hours.
01:32
We know all of this gives us one house complete.
01:39
We also know that without bess, with just bill and edi, it takes 15 hours.
01:47
So 15 hours of bill combined with 15 hours of edi also gives us one complete house.
01:59
And the last thing that we know is that if, if all three of them work for four hours.
02:10
So that's four of beth, four of bill, and four of ead.
02:21
And then we know that ead steps out and beth and bill work for an additional eight hours.
02:33
So that's eight more for beth and eight more for bill.
02:37
That that gives us one complete house.
02:41
So i'm going to rewrite these equations over here just so that i can combine some of this down here into one.
02:52
That way we have all of our equations really set and in the same form.
03:04
So the first two equations can stay the same.
03:07
They're already in that similar format.
03:11
For the second one, i could write.
03:13
Write a 0x at the beginning to indicate that beth isn't working, but that's just kind of implied by the fact that it's not there.
03:23
So here we have a total of 12x, a total of 12y, but only 4z.
03:41
And looking at the system of equations, there's a number of things you could do.
03:46
You could pull some substitution using this second equation, knowing that it would be pretty easy to solve for y or z in terms of the other.
03:59
But i'm actually going to use elimination with the first two equation, or the first equation and the last equation.
04:07
So i can see that to eliminate, i could get to a 60 by multiplying the first equation by six on both sides, and by multiplying my last equation by five on both sides.
04:24
So what that gives me is 60x plus 60y plus 60 z equals 6.
04:34
And my second equation gives me 60x plus 60y plus 20 z is equal to 5.
04:47
And then i'm going to subtract these two equations.
04:50
So that gives me 0x, 0y, 40z equals 1...