00:01
For this problem, we are asked to parameterize the cone in example 6 on page 1028 in terms of r and theta.
00:08
The first thing that i'll note about the cone on page 1028 is that we have that the cross -sectional area at the base is x squared plus y squared equals a squared.
00:21
Additionally, we can see that no matter what value of a we have, i .e.
00:27
No matter where we are along the cone, we are taking theta between 0 and 2 pi.
00:34
So we can immediately say, as i've indicated, 0 is less than or equal to theta is less than or equal to 2 pi.
00:42
Then, well, we know that we are trying to express this in terms of r and theta.
00:47
So, in that case, we want to make sure that we have some way of expressing r in terms of another parameter, or particularly in this case, z.
00:59
Since we will want to be expressing this with x, y, and z, we want to know explicitly how to express z in terms of r.
01:08
So how does z change? in this case, explicitly, we'd have that, let me write this down here.
01:17
Here, we'd have that a over h, where a is equivalent based on what we have here, a is equivalent to the maximum value of the radius.
01:31
So we may write that zero is less than or equal to r.
01:36
Zero is less than or equal to r, which is in turn less than or equal to a.
01:40
We have that a over h, where h is the overall height of our cone, will be equal to r over h.
01:50
If we rearrange this for z as opposed to for h as we see in the original example from the text, we have that z will be equal to 1 minus a or excuse me, let me correct myself here, 1 minus r over a all times h.
02:13
In that case, well currently we have z in terms of r, a and h...