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Problem 56 Easy Difficulty

Part $a$ of the drawing shows a bucket of water suspended from the pulley of a well; the tension in the
rope is 92.0 $\mathrm{N}$ . Part $b$ shows the same bucket of water being pulled up from
the well at a constant velocity. What is the tension in the rope in part $b$ ?


$[184 \mathrm{N}]$


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Video Transcript

in part a of the drawing. The book It Off Water is being sustained by this rope, which produces attention force and distension. Forces are counter acting the weight force in the first situation so we can apply Newton's second law on the first situation to calculate what is the weight off the bucket. So let me choose the reference frame for the Newton's second law as follows. Everything that is pointing up is pointing to the positive direction, and everything that is pointing down as a consequence is pointing to the negative direction. Therefore, applying Newton's second law to situation A, we get the following than that force is equals to the mass off the bucket times its acceleration note that the bucket is not moving anywhere. Therefore its acceleration is equal to zero. Then the net force that acts on the book. It is equal to zero on that situation. Then the forces that compose the net force in the situation are the two tensions and the weight forced reform. We have the following one tensions plus the order tension mind, as the weight foresees equals +20 then two times irritation is equals to do enforce the tensions. Egos to 92 noodles. Therefore, two times 92. Is he close to the weight, then the weight off the bucket is equals to 184 Newtons. Now on the situation be we can apply Newton's second law again, and this time we have the following. The net force is equal to the mass off the bucket times acceleration off the bucket. Now the buckets moving. But it's moving with a cause. That velocity, therefore acceleration is zero again. Then the net force steals being equals 20 But this time we have only one tension sustaining the bucket. Only this tension, which I had colored three t prime then the prime minus. The weight force is equal to zero. Therefore, t prime is equals to the weight force which is equals to 184 new terms. Then the tension on the rope In the second situation Yes, 184 new terms

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