Question
Particle A is projected vertically upward from a top of a tower. At the same time particle $B$ is dropped from the same point. The graph of distance (s) between the two particle varies with time is.
Step 1
At time t=0, both particles A and B are at the same point, so the distance between them is 0. Show more…
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A particle is projected vertically upwards from a points A on the ground. It takes time t1 to reach a point B, but it still continues to move up. If it takes further t2 time to reach the ground from point B. Then height of point B from the ground is:
From a tower of height $H$, a particle is thrown vertically upwards with a speed $u$. The time taken by the particle to hit the ground is $n$ times that taken by it to reach the highest point of its path. The relation between $H, u$ and $n$ is (A) $2 g H=n^{2} u^{2}$ (B) $g H=(n-2)^{2} u^{2}$ (C) $2 g H=n u^{2}(n-2)$ (D) $g H=(n-2) u^{2}$
From a tower of height $H$, a particle is thrown vertically upwards with a speed $u$. The time taken by the particle, to hit the ground, is $n$ times that taken by it to reach the highest point of its path. The relation between $H, u$, and $n$ is:(a) $2 \mathrm{~g} H=n^{2} u^{2}$ (b) $\mathrm{g} H=(n-2)^{2} u^{2}$ (c) $2 \mathrm{~g} H=n u^{2}(n-2)$ (d) $\mathrm{g} H=(n-2)^{2} u^{2}$
KINEMATICS
Motion in a Straight Line
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