Question
People have proposed driving motors with the earth's magnetic field. This is possible in principle, but the small field means that unrealistically large currents are needed to produce noticeable torques. Suppose a 20 -cm-diameter loop of wire is oriented for maximum torque in the earth's field. What current would it need to carry in order to experience a very modest $1.0 \times 10^{-3} \mathrm{N} \cdot \mathrm{m}$ torque?
Step 1
The diameter is given as 20 cm, so the radius will be half of the diameter, which is 10 cm or 0.1 m. \[ r = \frac{d}{2} = \frac{20}{2} = 10 \, \text{cm} = 0.1 \, \text{m} \] Show more…
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