perform-the-indicated-operations-and-write-the-result-in-simplest-form-b2b3-b5

Question

Perform the indicated operations and write the result in simplest form.
$b^{2}+b(3 b+5)$

M S · Accepted Answer

So we have B squared plus B times three b plus spot. Do not mistake this as B squared plus B times three me plus bug because it&#x27;s not that, As you see, we don&#x27;t have parentheses here. It&#x27;s just the beating times. So that just means we&#x27;re going to distribute this be here and here so we&#x27;ll just bring down our B squared. We don&#x27;t have anything to combine it with you and never gonna multiply on B times three b and I would give us plus three b squared because one plus one is two and everyone&#x27;s a part is me time since fire. When I give us by B Now we can combine these. So we have one place three, which is for, you know before B squared close, far be

M S · Answer

So we have to buy no meals and we&#x27;re gonna multiply them. So when everyone supply to buy no meals, we use the for your method. So, first outer anyway, unless serve animal supply 1st 2 terms five B times. Bobby five times five is 25 and then we add those exponents. So that gives us two. They would do the outer times two times five. Dog doesn&#x27;t know you too. And then only variable is B. They would do the inner terms two times five is to not because it at this time and the only variable speed And then we do our last terms two times negative attitude against us. Negative for So because these two have the same exponents in the middle, we can combine the coefficients. So we have 25 b square negative 10 respondents engines and see rose. So the coefficient of zero be in that just councils. And then we&#x27;ll run down our minus four

Derrick Hanson · Answer

to start this problem off were given to buy no meals. They&#x27;re supposed be multiplied to each other, which means that would be a foiling problem. So to be times five B for the first terms would give us 10 B squared to be times negative. One for the outer terms would give us negative to be three times five b for the inter terms would give us positive 15 B and three times negative one for our last terms would give us negative. Three. Cleaning that up. We would have 10 b squared minus Sorry, not Maya&#x27;s. Let&#x27;s have a plus 13 b negative to be plus 15 b would be positive 13 B minus three. For a second part of this problem, we have were given B plus two squared sweet one. Take care of that by using our special product rule right here. So we&#x27;d start by squaring the first term, which would give us B squared plus two times the first term times the second term two times B would be to be to be times to would be four B and finally plus our second term squared two squared is for now that we&#x27;ve taken care of all the multiplication. We can move on to the subtraction where we can combine our like terms to get a final answer. 10 B squared minus B squared would be nine b squared 13 B minus four b would be nine b negative. Three minus four would be negative seven. Giving us a final answer of nine B squared plus a nine B minus seven.

Aditya Sood · Answer

perform that indicated operations and read the result in simplest form. The expression were given is to a to the first B squared times seven a cube B squared so we can simply rewrite this. We can rewrite this and keep the same terms together. So let&#x27;s just rewrite this to get the A&#x27;s over here and keep bees over here. So now we can further simplify these together. So two times seven is 14 and when you&#x27;re multiplying powers, you can simply add their power together. So, age of the first times a cube. It&#x27;s the same thing as a to the eight. So we get 14 8 to the eighth Power times, and on this side we have B Square 10 p squared. So this is the ceiling is one B squared times one B squared. And so when you multiply one and one together, the call fishing, it&#x27;s going to be one and b squared. We can once again we can add the exponents to get big the fourth. So we were left with 14 8 to the eighth B to the fourth, and that is her answer. In simplest form,

M S · Answer

so we have to be minus two. All squared. So whenever we see that squared exponents, that just means we&#x27;re gonna multiply the binomial by itself. So we have three t minus two times three B minus two. And because we&#x27;re not supplying to buy no meals, we&#x27;re gonna use the foil minted. So what have the first chowder, then enter terms. And in the last terms, this just helps us keep everything orderly. Someone for the 1st 3 many times three be not only those 29 b squared because we have those explain it. Don&#x27;t do the outer terms so negative two times three is negative six and then just bring on that b turned it. Enter terms and same thing here. Negative two times three is negative. Six. Hey! And almost part of the last times negative times Negative gives us positive for so because he&#x27;s too in terms in the middle, have the same Explain it. We can combine the coefficients so have nine b squared in the year six minus six is negative 12 b and then plus fours

Ankit Gupta · Answer

in this question, we have to simplify given expiration Find a B D right 80 Fire A steady minus p Step less It must be. You are Goodbye. A minus, bi. No. We have to combine the two elections by finding a woman, you know. So we find a least woman multiple and then simplify the given expression. So we get ISS where plus five a b less way B plus B squared You are ended by a minus bi where did never a plus B Now on combining the numerous doesn&#x27;t then simplifying good bigot is great plus seven a B plus B square You are guided by a minus Bi bi did lever a plus me

Problem

Perform the indicated operations and write the re…

Problem 20 Easy Difficulty

Perform the indicated operations and write the result in simplest form.
$b^{2}+b(3 b+5)$

Answer

$4 b^{2}+5 b$

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Ann Xavier Gantert

Algebra 2 and Trigonometry

Grace H.

Catherine R.

Anna Marie V.

Heather Z.

Absolute Value - Example 1

Absolute Value - Example 2

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$4 b^{2}+5 b$

Algebra 2 and Trigonometry

Grace H.

Catherine R.

Anna Marie V.

Heather Z.

Absolute Value - Example 1

Absolute Value - Example 2

Ann Xavier GantertAlgebra 2 and Trigonometry

Grace H.

Catherine R.

Anna Marie V.

Heather Z.

Ann Xavier Gantert

Algebra 2 and Trigonometry