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Problem

Perform the operations and, if possible, simplify…

01:52

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Meredith M.

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101 Problem 102 Problem 103 Problem 104 Problem 105 Problem 106 Problem 107 Problem 108 Problem 109 Problem 110 Problem 111 Problem 112 Problem 113 Problem 114 Problem 115 Problem 116 Problem 117 Problem 118 Problem 119 Problem 120 Problem 121 Problem 122 Problem 123 Problem 124

Problem 93 Medium Difficulty

Perform the operations and, if possible, simplify.
$$
\frac{4}{3}\left(\frac{6}{5}\right)
$$

Answer

$\frac{8}{5}$

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Elementary and Intermediate Algebra

Chapter 1

An Introduction to Algebra

Section 2

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Video Transcript

Mr Tutorial goes through solving problem 93 from chapter one section to practice. We're told to perform the given operations and then simplify it possible. So what I'm going to do is I'm going to rewrite this. So it looks like the operation, a more familiar form of the operation, which is multiplication. So for six times six pics and then I could multiply for 10 6 on, then get 24/6 times five and get 30. Honestly, I can see that they have this common factor of six. So I am going to do what is sometimes called cross canceling. Were dividing out a common factor before you even multiply because six divided by six is one. And so that leaves me with 4/5. Yeah, If you don't believe me, take a look at this. So four times six is 24 over six times five, which is 30. If I prime factor that I get to times 12 on 12 is two times two is four times two times three. Um, started out two times. Three times three. Firm is 12. So two times four times three is 24 then 60 a 30 is six. So two times 36 times five And then they share too. And they share a three. That these US two times two is four. And so there it up. But I saved myself so much work by removing the factors at the beginning rather than waiting until I multiply.

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Alan S. Tussy, R. David Gustafson

Elementary and Intermediate Algebra

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