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Perform these calculations for nickel(II) carbonate. (a) With what volume of water must a precipitate containing $\mathrm{NiCO}_{3}$ be washed to dissolve 0.100 $\mathrm{g}$ of this compound? Assume that the wash water becomes saturated with $\mathrm{NiCO}_{3}\left(K_{\mathrm{sp}}=1.36 \times 10^{-7}\right)$(b) If the NiCO_ were a contaminant in a sample of $\operatorname{CoCO}_{3}\left(K_{\mathrm{sp}}=1.0 \times 10^{-12}\right),$ what mass of $\mathrm{CoCO}_{3}$ would have been lost? Keep in mind that both NiCO_ a and CoCO_ dissolve in the same solution.

a. 2.28 $\mathrm{L}$b. $7.3 \times 10^{-7} \mathrm{g}$

Chemistry 102

Chapter 15

Equilibria of Other Reaction Classes

Chemical Equilibrium

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I have one. This is Ricky, and today we're working on problem 41. So we need We have, um, 0.100 grams of mickle carbonate. Um, how much water will it take to resolve this? Give him that. The case p is 1.36 times 10 to the night of seven. So let's write out our K s p. A quaint expression on. Before we can do that, we need to write association equation for on the carbonate and water. And I and I was too the CEO of minus two, so Case P is equal to and I plus two c 03 Why miss too? Um, we are solving for the concentrations. You know, case P one on 36 times seven people too, huh? Is equal to x Times. X X is equal to 3.68 Nine times 10 to me. Negative fourth Moeller. And now, to calculate the saw the ability in or how much water is required, member moles are My clarity is moles the theater and we want to convert this two grams per leader. And so the way that we do this is by multiplying Moeller soluble ity by the molar Mass. Um, which is 118 on 71 grams more moles cross out, and we get that. The volume of water that can dissolve point to one grams is nickel carbonate is to want to eight theaters. All right, And then the second part of the question is s So we have a sample of Cobalts carbonate, right? Has been contaminated in the carbonate. What massive cobalt carbonate was lost. All right, so uh huh. We know that the concentration of carbonate is the same as an A. So it's three minus two is equal to 3.6 eat. No, I just want to make it forth. We know the S ky. So you can write the equation. So first, that's right. Our disassociation waiting CEO Seo three dissolves into Seo is to seal me minus two. So the cast B is equal to CEO plus two cell three minus two. Now we want to solve for the concentration of go boat. So let's isolate that Just plug and Shug and we get a concentration of 2.71 Time center Negative nine Moeller and then we know the mass of CEO CEO Seo three is equal to molar mass of CEO Seo Free, which is 118 94 grams per mon times. The Moler saw the ability we just calculated 2.71 times 10 to the next nine malls per liter, sometimes the volume of water. It's 2.28 leaders, which is from a You did this crosses out, moles, crosses out and we're left with 7.3 times 10 to the negative seventh grams of cobalt or of CEO Seo three lost. All right, so but this video is helpful.

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