00:01
Hello everyone.
00:01
This is ricky.
00:03
And today we're working on problem 41.
00:07
So we need, we have 0 .100 grams of nickel carbonate.
00:16
How much water will it take to dissolve this, given that the ksp is 1 .36 times 10 to the negative 7.
00:24
So let's write out our ksp equate expression.
00:34
And before we can do that, we need to write the dissociation equation for nickel carbonate and water.
00:43
N .i.
00:44
Co3, ni plus 2, co3 minus 2.
00:55
So ksp is equal to ni plus 2, co3 minus 2.
01:07
We are solving for the concentrations.
01:11
We know ksp 1 .36 times 10 to negative 7.
01:15
Is equal to x times x x is equal to 3 .689 times times 10 to the negative fourth molar.
01:44
And now to calculate the solubility and or how much water is required.
01:55
Remember, molarity is moles per liter.
02:01
And we want to convert this to grams per liter.
02:05
And so the way that we do this is by multiplying the molar solubility by the molar mass, which is 118 .71 grams per mole.
02:20
Moles cross out.
02:22
And we get that the volume of water that can dissolve...