Question
Phenol, $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH},$ has a $K_{a}$ of $1.3 \times 10^{-10}$(a) Write out the $K_{a}$ reaction for phenol.(b) Calculate $K_{b}$ for phenol's conjugate base.(c) Is phenol a stronger or weaker acid than water?
Step 1
(a) The Ka reaction for phenol is the dissociation of the phenol molecule into its constituent ions in water: C6H5OH (aq) ⇌ C6H5O- (aq) + H+ (aq) Show more…
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Phenol, $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH},$ has a $K_{a}$ of $1.3 \times 10^{-10}.$ (a) Write out the $K_{a}$ reaction for phenol. (b) Calculate $K_{b}$ for phenol's conjugate base. (c) Is phenol a stronger or weaker acid than water?
Phenol $\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right),$ commonly called carbolic acid, is a weak organic acid. $$\begin{array}{c} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}(\mathrm{aq})+\mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq}) \\ K_{\mathrm{a}}=1.3 \times 10^{-10} \end{array}$$ If you dissolve $0.195 \mathrm{~g}$ of the acid in enough water to make $125 \mathrm{~mL}$ of solution, what is the equilibrium hydronium ion concentration? What is the pH of the solution?
Phenol $({C}_{6} {H}_{5} {OH}, K_{{a}}=1.3 \times 10^{-10})$ is a weak acid used in mouthwashes, and pyridine $\left({C}_{5} {H}_{5} {N}, K_{{b}}=1.8 \times 10^{-9}\right)$ is a weak base used as a solvent. Calculate the value of $K_{{n}}$ for the neutralization of phenol by pyridine. Does the neutralization reaction proceed very far toward completion?
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