00:01
For this problem, we have a person distribution with a rate of 48 per hour.
00:12
And for the first problem, we are to compute the probability of receiving three calls in a five minute interval of time.
00:23
So for a five minute interval, the mean is given us 5 over 60 times 48.
00:31
This is equal to 4.
00:36
Therefore, probability of 3 calls is equal to the mean that is 4 to the power x, that is 3.
00:53
You have the exponent of negative 4 divided by x factorial, that is 3 factorial.
01:08
This is equal to 0 .1954.
01:15
Now p of x for any personal distribution is given us the mean.
01:23
Is the power x and we have the exponent of negative mu divided by x factorial so to the next question we are to compute the probability of receiving exactly 10 calls in 15 minutes for 15 minutes the average number of course is 15 divided by 60 times 48 that is equal to 12 therefore the probability of 10 calls will be equal to the average you have 12 based to the power 10 then the exponent of negative 12 divided by 10 factorial and this is equal to 0 .1048.
02:43
In the next problem suppose there are no calls currently on hold if the agent takes five minutes to complete the current call how many callers do you expect to be waiting by that time...