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Phosphorus forms many oxoacids. Indicate the oxidation number of phosphorus in each of the following acids: (a) $\mathrm{HPO}_{3},$ (b) $\mathrm{H}_{3} \mathrm{PO}_{2},$ (c) $\mathrm{H}_{3} \mathrm{PO}_{3}$(d) $\mathrm{H}_{3} \mathrm{PO}_{4},(\mathrm{e}) \mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{7},$ (f) $\mathrm{H}_{5} \mathrm{P}_{3} \mathrm{O}_{10}$

A. $x=+5$B. $x=+1$C. $x=+3$D. $x=+5$E. $x=+5$F. $x=+5$

Chemistry 102

Chapter 4

Reactions in Aqueous Solutions

Solutions

Aqueous Equilibria

Rice University

University of Maryland - University College

Brown University

University of Toronto

Lectures

03:58

In chemistry, a solution is a homogeneous mixture composed of two or more substances. The term "solution" is also used to refer to the resultant mixture. The solution is usually a fluid. The particles of a solute are dispersed or dissolved in the solvent. The resulting solution is also called the solvent. The solvent is the continuous phase.

00:41

In chemistry, an ion is an atom or molecule that has a non-zero net electric charge. The name was coined by John Dalton for ions in 1808, and later expanded to include molecules in 1834.

06:01

Give the oxidation number …

01:03

02:36

Assign an oxidation state …

So come from for question 40 requires to define the ocidation number of the papers on the term on the compound here we see that neutral, but keep in mind and forget the neutral come in neutral compound oscitation that equals the total oxidate of the elements in the Campo equals 0 point so, based on this row, we can find a ocidation that prose. I first want a a p 03 and we know also your own way that minus 1 right away- minus 1, hydrogen and plus 1 point. So we got here, as we don't know as to the oxidation of a out, and we know the total ocidation in the neutral compels 0 and this neutrals. We didn't see that jack here. So i got parminoxygen here only 1 plus 1 plus s m s 3 times 2 misqals 0 point so solve in the equation. We know now i got to manilas minus 5 so, as should be equal plus 5 bay at 33, p o 2. This you at 3 p, o 2. Here are 3 p, o 2. Okay, now we have at 3 p, o 2 point again so y plus 1 hydrogen and y plus 1 asigntwo keeping my oxygen only get negative 1 in a pair of sin, us 1, with the florine and hydrogen or eat plus 1 set hydra. The compass of hydrogen with the meteor, the hydra hydrogen minus 1 point, so we could here this will be 3 times plus 1 and plus 2 times. Minus 2 equals 0 point, so this would be equivalent. What does the 3 lots at enator here? So i still be a 1 b c at 3 p, o 3, the same as here and 3 have this 1, not at the 3. Minus 2 equals 0 point. So this will be l 3 plus a m t minus 6 quaero. So as a co, lustre, das, 4 p 2 o at 3 d, o 4 d at 3, p, l 4 for haridases same here as here so 3 plus 1 plus x, plus 4 times minus 2 equals 0 point. So we got here: 3 plus plus x, plus 8, equals 0 point so should equal, i has should be equal plus 5 or e e, a 4 p, 2 o 7, the same as here for them plus 1 to 2 s plus 7 times 2 equals 0 Point so how do we go? What like plus 4 here, i'm not to as here lafourteen here equals 0 point, so that told us plus minus 10 point right, equals 0 point, so i up 1 plus 5 and that's the last 1, a f half at 3. At 5 b, 3, o 10 and 5, p, 3 or 10 point the same as here 5 times as 1, not 3 as plus pi minus 2 equals 0 is comin, 16 equal 3 s equals plus 5, and this work like 3 s plus minus 11, o 53, as what's wrong here, no longer 53 s and 2, a tent. That'S why i don't know why i got this 1. I see it. I got to be 10 here if so prithat's, what i'm so surprised, but why? I'M so surprised here that tent that much in so i gave my grand here and now the suite here, so i should be equal plus 5. I supply y papers can be fraction. I got my sub wonder:

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