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Place these salt solutions, NaCl(aq), in order of increasing molarity.a. 4.0 mol per 8.0 Lb. 6.0 mol per 6.0 Lc. 1.0 mol per 10 L

a.) $(4.0 \mathrm{mol} / 8.0 \mathrm{L})=0.50 \mathrm{M}$b.) $(6.0 \mathrm{mol} / 6.0 \mathrm{L})=1.0 \mathrm{M}$c.) $(1.0 \mathrm{mol} / 10 \mathrm{L})=0.10 \mathrm{M}$

Chemistry 102

Chemistry 101

Chapter 15

Toxins in Solution

Section 1

Solution Concentration

Solutions

Composition

Chemical reactions and Stoichiometry

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in problem five. Place this whole solution in order off increasing McGarity. So first is formal, but it later So morality is simply number off multiplied by the volume off solution in later. So number off mall is four and volume is it. So we get this value is 0.5 Mueller. So this is theme Alere ity. So in part B so in the part B, that is six small but six later So Malard charity is number off mall divide by volume off solution in later So number off Molly six volume mystic. So we get one Moeller So this is 10.5 Mueller and this is get one Moeller solution And in the party that is one mole one mole But then later So Mueller iti is number off more divided by volume of solution in later So one Burton which is equal to 0.1 Mueller So we find out the three solutions So formula Retty off three solutions So for solution it is 0.50 point five Moeller Solution B is one Mueller solution See is zero find one Mueller So clearly we can say that solution be That means the increasing order off hilarity off solutions are so we can write it. Write it as increasing order off mill arat E increasing order off polarity. That is C mhm Be that when B is hi majority than is less and see is very less so So solution a solution We see that the solution be solution mhm and solution c So C is 0.1 Moeller solution a solution B is one Moeller and the solution is solution is 0.5 Muller So like this we can say that So this is the increasing order off hilarity off the solution.

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