00:01
So for this problem, we know that we have platinum that forms two different compounds with chlorine and only chlorine.
00:07
And you know that one of them contains 26 .7 % chlorine.
00:13
And the other one of them contains 42 .1 % chlorine.
00:18
And these are both percent by mass.
00:20
And we want to find the empirical formula for both these compounds.
00:23
So let's first do the compound with 26 .7 % chlorine.
00:28
So like we're always going to do with percent mass problems.
00:31
We're going to assume that the compound is 100 grams.
00:38
And if we assume that it's 100 grams, we know that 26 .7 % of that, or 26 .7 grams of that, is going to be chlorine.
00:48
And thus we know that the remaining is going to be platinum.
00:54
And so when you subtract those values out, we get 73 .3 grams of platinum.
01:02
Now, we just want to find their relative multiple ratios.
01:06
So we take 73 .3 grams of platinum.
01:15
And then we divide by its atomic mass, which is 195 .08 grams per one mole of platinum.
01:26
And then we multiply that through, we get 0 .376 moles of platinum.
01:34
We're going to do the same thing with chlorine.
01:36
We have 26 .7 grams of chlorine.
01:42
And in every mole of chlorine, there is 35 .45 grams.
01:49
And when we multiply that out, we get 0 .75 moles of chlorine...