00:01
So in this particular problem, we're asked to do several things.
00:03
So first of all, we need to identify alpha.
00:06
The significance level is 1 % 0 .01.
00:10
And we know that the null hypothesis is that p is 0 .301.
00:17
And then the alternate hypothesis would be that p is less than.
00:22
Now, to figure out what kind of distribution it is, it's going to be standard normal.
00:28
And a quick check is n times p greater than five and indeed it is so 215 times 0 .301 is indeed greater than 5 because it equals 64 .7 about and then is n times q greater than 5 so if p is 301 then 1 minus 0 .301 will give us q, so q will be 0 .699.
01:10
So when i multiply those together, 2 .15 times 0 .699, i get approximately 150, so yes, that is indeed greater than 5.
01:27
Now i need to find the test statistic, which in this case will be p hat, and they're asking us to find the z value.
01:34
So i'm going to do this all at once with my calculator.
01:36
I've already got it worked out, but let me walk through it with you.
01:39
So stat tests, this is a one proportion z test, so number five.
01:47
Now the probability of success is 0 .301.
01:51
We're told that r is 46.
01:53
So in the calculator, that's the x.
01:56
The total population is 215.
02:00
We're testing if it's actually a less than cursor down to calculate.
02:06
And the information i need is all right there.
02:08
So i have this on the other screen.
02:17
So p hat is 0 .21, depending on rounding here.
02:27
2 .14 and z is negative 2 .78...