00:01
So we're assuming that these two means are equal and alternately just that they're different.
00:09
So, and we're told that the distributions are mound shaped so that we need not, and we have random data, so we need not worry about the small sample sizes of seven and eight.
00:20
And so we're going to be assuming that that mean difference between these two is zero.
00:26
Now in reality, x bar 1 minus x bar 2 is 4 .86 minus the 6 .5.
00:37
Well, let's put the 6 .5 up this way.
00:41
And so when we subtract those two values, we are going to get a negative difference in this case.
00:47
The 4 .86 minus the 6 .5 is going to give us that negative mean of 1 .6.
00:56
So we're getting a value down here of negative 1 .64, and we want to find that tail and that tail, where this is positive 1 .64 for the test statistic.
01:08
It will be a t value because we don't know the population standard deviation, and we have our difference that we have that 4 .86 minus the 6 .5, which we know that that difference is negative 1 .64, minus the 0 that we're assuming that.
01:27
That difference is equivalent to.
01:29
And then we're going to divide by the standard deviation squared, divided by the sample size, and the other standard deviation squared divided by its sample size.
01:41
And again, both sample sizes are pretty small, but this test is robust when we have mound shape curves.
01:47
So we can still continue...