00:01
So we're going to assume that the mean of the first group is equal to the mean of the second group for water content.
00:07
And alternately, the mean of the first group is higher than the mean of that second group.
00:13
And we have mound shape distributions that are symmetrical in random samples.
00:19
So we'll be fine with using our sample sizes of 14 and 16 because of that shape.
00:27
Now, we want to look at our distribution, and we know we're going to be assuming that the difference between the two means is equal to zero.
00:38
But we're getting the x bar 1 minus the x bar 2 to be this 12 .53 minus the other x bar is 10 .77.
00:51
And so i could get my calculator and do that, but let's just quick do it.
00:55
So we have a six here and then that's going to be a seven.
00:59
So 1 .76 is what that difference is, 1 .76 for the difference between the means.
01:06
And we're going to want to find that p value.
01:08
And because we don't know our population standard deviations, we'll be finding test statistic that is a t.
01:14
We'll take the difference we got minus the difference we're assuming, divided by the square root of the standard deviation, which the first one was 2 .39 .2 .3.
01:25
Divided by the sample size of 14 and the other one is 2 .4 squared divided by the sample size of 16...