00:01
All right, so we're asked to find the graph to the right of x being greater than negative 1.
00:08
So that's all i'm doing right now is showing the graph to the right of x equals negative 1.
00:16
And you probably remember in a pre -couculous, there's a lot of tricks to doing this.
00:24
For instance, if you look at 4x over x plus 1 squared, that you can set the numerary number.
00:32
Equal to 0.
00:34
If you set the numerator equal to 0, that will find, well, the y value equals 0.
00:41
So that only happens when x equals 0, because you can divide the 4 over.
00:45
So x equals 0.
00:47
So the ordered pair 0 is on the curve.
00:51
If you set the denominator equal to 0, change colors, that'll find you the vertical asymptote, which is exactly happening there.
01:00
Now what you don't know is what kind of curve you have.
01:05
Let me make sure.
01:08
So what they want you to do is to take the derivative of that, which would be your quotient rule.
01:14
So they had this as y equals.
01:16
So d, y, d, x, is equal to the derivative of the top, leave the bottom alone, minus the derivative of the bottom, which is your chain rule.
01:29
X plus 1 is now to the first power.
01:30
Leave the top alone.
01:32
All over the denominator.
01:33
It is squared.
01:36
So x plus one would be to the fourth power because squared squared is to the fourth.
01:40
Now what i would do is i would try to simplify a little bit.
01:44
For instance, every one of these terms has an x plus one.
01:48
So i can now take out an x plus one and cancel it out.
01:52
So we're looking at four...