- The unit circle in this norm is defined by the set of points \((v_1, v_2)\) such that \(\|\mathbf{v}\| = 1\).
- Substitute into the norm equation: \(\sqrt{v_1^2 + 4v_2^2} = 1\).
- Square both sides to remove the square root: \(v_1^2 + 4v_2^2 = 1\).
- This
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