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Point charges of 25.0$\mu \mathrm{C}$ and 45.0$\mu \mathrm{C}$ are placed 0.500 $\mathrm{m}$ apart. (a) At what point along the line between them is the electric field zero? (b) What is the electric field halfway between them?

a)0.214 $\mathrm{m}$b)$-2.88 \cdot 10^{6} \frac{\mathrm{N}}{\mathrm{C}} \hat{x}$

Physics 102 Electricity and Magnetism

Chapter 18

Electric Charge and Electric Field

Rutgers, The State University of New Jersey

University of Washington

Hope College

Lectures

11:53

In physics, a charge is a …

10:30

The electric force is a ph…

06:58

Two $2.00-\mu \mathrm{C}$ …

08:41

A 3.4$\mu$C and a -2.6$\mu…

06:03

$\bullet$ $\bullet$ Two pa…

06:00

04:17

Point charges of $5.00 \mu…

03:54

Point charges $q_{1}=50 \m…

04:30

Two point charges are sepa…

Two point charges are on t…

04:05

Two charges are placed on …

02:35

What is the magnitude of t…

01:30

$A-10.0$ nC point charge a…

0:00

Two tiny objects with equa…

07:03

A charge of $-2.505 \mu \m…

03:03

What are the magnitude and…

12:41

03:37

At a certain distance from…

05:28

Two stationary point charg…

05:56

(II) Two point charges, 3.…

02:07

How far from a $-7.20 \mu …

07:04

The electric field at the …

I'm Savino. The electric field is England Will take you r squared, right? And so, at any point in between these charges, each you one point over design on each you tour point over the side rate until the indeed will cancel each other out. And we just need to equate basically, um, key. You weren't r One squared ski can do over our two square eight on. If you take the distance through you want to be X So you just cut out cation bow tie into the equation, Ondo trying find micro cool. So you distinct 25 where explain is equal to 45 over zero coin find minus X squared. Right, Because I don't need the distance. Shouldn't you do? And now just solving this equation we get equals 45 express just in the square load on both right rate. We get trying the one by minus X People's plus minus through 45. Rex, I'm just a case e with by 0.5 minus X is equal to room 45 x Solving this we'll get 2.5 is in Quito 45 plus five whole into X and then just taken this that side we'll get X is the group zero point, the one who does. I'm just to show you that viable winners reject gay spee, which is basically a five by minus X minus 45 x because all English, we get X as 97.46 meters, which doesn't make sense or indoor convention. So we just did inject to this value right and me with you're going to want to meet us. And now for part B of the question way, we need to find the electric field half between them, right? So, as I stated before the electric field, one will be the same and you two will be the opposite direction. As we know the magnitude of each will be more than a month of each ward simply because years take you with our sweat. And aboard these cases, kids, a constant are will be same in both cases and you, the larger magnitude is 45 then 25. Great, So just to make paralyzing E net is going to be Q minus you one which is basically G over our square. You're going to find square, which is basically the distance between the charges upon through that maze. 40 fine, minor, strange fight. Do you and Mom minus six, a Mississippi radio going 80 into and Fast six Newton for Fulham in the direction off the judo in that tonight.

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