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$$\begin{aligned} \text { Find the ratio of } x \text { to } y : \frac{4}{y}+\frac{3}{x} &=44 \\ & \frac{12}{y}-\frac{2}{x}=44 \end{aligned}$$

Points $B$ and $C$ lie on $\overline{A D}$ . Find $A C$ if $\frac{A B}{B D}=\frac{3}{4}, \frac{A C}{C D}=\frac{5}{6},$ and $B D=66$

52.5

We know that a C over C. D is five divided by sex. Therefore, we know five sex times 63 because remember CDs 63 this gives us 52.5.

Given points $A, B,$ and $C .$ Find $A B, B C,$ and $A C .$ Are $A, B,$ and $C$ collinear? If so, which point lies between the other two?$$A(-5,6), B(0,2), C(3,0)$$

Given points $A, B,$ and $C .$ Find $A B, B C,$ and $A C .$ Are $A, B,$ and $C$ collinear? If so, which point lies between the other two?$$A(3,4), B(-3,0), C(-1,1)$$

Given points $A, B,$ and $C .$ Find $A B, B C,$ and $A C .$ Are $A, B,$ and $C$ collinear? If so, which point lies between the other two?$$A(0,3), B(-2,1), C(3,6)$$

Show that the points $A(-4,-5), B(1,1),$ and $C(6,7)$ are colinear.Hint: Points $A, B,$ and $C$ lie on a straight line if $A B+B C=A C$

Given points $A, B,$ and $C .$ Find $A B, B C,$ and $A C .$ Are $A, B,$ and $C$ collinear? If so, which point lies between the other two?$$A(5,-5), B(0,5), C(2,1)$$

Use mental math to find a, b, c, and d.$$\left[\begin{array}{rr}3 a & 5 b \\c-6 & d\end{array}\right]=\left[\begin{array}{rr}-12 & -5 \\1 & -3\end{array}\right]$$

Points $A$ and $B$ are given. Make a sketch. Then find $\overrightarrow{A B}$ and $|\overrightarrow{A B}|.$$$A(6,1), B(4,3)$$

Find $a, b, c,$ and $d$ so that$$\left[\begin{array}{ll}1 & 3 \\1 & 4\end{array}\right]\left[\begin{array}{ll}a & b \\c & d\end{array}\right]=\left[\begin{array}{ll}6 & -5 \\7 & -7\end{array}\right]$$

Points $A$ and $B$ are given. Make a sketch. Then find $\overrightarrow{A B}$ and $|\overrightarrow{A B}|.$$$A(1,1), B(5,4)$$

Three points that lie on the same straight line are said to be collinear. Consider the points $A(3,1), B(6,2),$ and $C(9,3) .$Repeat Exercise 99 for the points $(0,6),(4,-5),$ and $(-2,12)$

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## Discussion

## Video Transcript

We know that a C over C. D is five divided by sex. Therefore, we know five sex times 63 because remember CDs 63 this gives us 52.5.

## Recommended Questions

Given points $A, B,$ and $C .$ Find $A B, B C,$ and $A C .$ Are $A, B,$ and $C$ collinear? If so, which point lies between the other two?

$$A(-5,6), B(0,2), C(3,0)$$

Given points $A, B,$ and $C .$ Find $A B, B C,$ and $A C .$ Are $A, B,$ and $C$ collinear? If so, which point lies between the other two?

$$A(3,4), B(-3,0), C(-1,1)$$

Given points $A, B,$ and $C .$ Find $A B, B C,$ and $A C .$ Are $A, B,$ and $C$ collinear? If so, which point lies between the other two?

$$A(0,3), B(-2,1), C(3,6)$$

Show that the points $A(-4,-5), B(1,1),$ and $C(6,7)$ are colinear.

Hint: Points $A, B,$ and $C$ lie on a straight line if $A B+B C=A C$

Given points $A, B,$ and $C .$ Find $A B, B C,$ and $A C .$ Are $A, B,$ and $C$ collinear? If so, which point lies between the other two?

$$A(5,-5), B(0,5), C(2,1)$$

Use mental math to find a, b, c, and d.

$$

\left[\begin{array}{rr}

3 a & 5 b \\

c-6 & d

\end{array}\right]=\left[\begin{array}{rr}

-12 & -5 \\

1 & -3

\end{array}\right]

$$

Points $A$ and $B$ are given. Make a sketch. Then find $\overrightarrow{A B}$ and $|\overrightarrow{A B}|.$

$$A(6,1), B(4,3)$$

Find $a, b, c,$ and $d$ so that

$$\left[\begin{array}{ll}

1 & 3 \\

1 & 4

\end{array}\right]\left[\begin{array}{ll}

a & b \\

c & d

\end{array}\right]=\left[\begin{array}{ll}

6 & -5 \\

7 & -7

\end{array}\right]$$

Points $A$ and $B$ are given. Make a sketch. Then find $\overrightarrow{A B}$ and $|\overrightarrow{A B}|.$

$$A(1,1), B(5,4)$$

Three points that lie on the same straight line are said to be collinear. Consider the points $A(3,1), B(6,2),$ and $C(9,3) .$

Repeat Exercise 99 for the points $(0,6),(4,-5),$ and $(-2,12)$