poisoning-with-mercury-chloride-can-be-reversed-by-chelation-therapy-the-chelating-agent-called-edta

Question

Poisoning with mercury chloride can be reversed by chelation therapy. The chelating agent called EDTA, $\mathrm{C}_{10} \mathrm{H}_{16} \mathrm{N}_{2} \mathrm{O}_{8},$ is injected into the bloodstream. EDTA forms a water-soluble compound with mercury ions, allowing removal from the body through the kidneys.
$$\mathrm{HgCl}_{2}(s)+\mathrm{C}_{10} \mathrm{H}_{16} \mathrm{N}_{2} \mathrm{O}_{8}(a q) \longrightarrow \operatorname{HgC}_{10} \mathrm{H}_{12} \mathrm{N}_{2} \mathrm{O}_{8}(a q)+4 \mathrm{HCl}(a q)$$
a. Write an interpretation of the chemical equation.
b. What do you expect to observe?

Vishal Sharma · Accepted Answer

So in this problem, we have given a reaction in which Mercury chloride rips with the duty which is See you then at 16 and toe oiled. So this is the co solution off media e d d. So it will form this product. So this is the product form and let&#x27;s see it. So this is the product formed when mercury chloride reactivity id et. So the question in the party off the so party off the question is the right and interpretation off the chemical reaction So so party. We can see from the equation when soldered mercury chloride. So this is the mercury chloride when sold it mercury chloride. So as we see that from the equation, as represents the solid so mercury chloride the face off mercury chloride a solid so when solid mercury chloride is added to a solution off within the year is added towards solution. All solution off you day bu to produce a solution containing to produce a solution containing containing ah, compound off Mercury Ah, compound all mercury and a compound off mercury with DDT with a deity and hydrochloric acid. Higher truth, glory answered, which is at CNN. So this is the interpretation we find out from the chemical from this reaction. So in the part B off the ocean is that is what do you expect, toe observe. So from this reaction so we can see that if there to react INTs if they toe reactant are mixed, are mixed in the reaction the solid will disappear, the solid will disappear. And that mixture off and a mixture off to liquid make sure off, So liquids that remains so. So this this is the a reaction. So this is the again in Equus solution. So we see that this soldier is disappeared in the product side that is present in the reactor inside off the reaction So here, as represents the solid face and a cure, represents the echoes face in the reaction equals phase that is shown in the chemical reaction

Aadit Sharma · Answer

in case off lead poisoning. The intravenous injections off E D. P will be given and the reaction undergoes will be let baby to positive in presence off e d d. Needs to formation off a complex lead. E d d. To positive. So the formation constant will be concentration off product divided by the concentration off reactions. The concentration off e D. T in the blood off patient is already given and the formation constant for complex is also given. So we subsidy or the values into equation, too. We have point Tzeitel, 10 days to power 18 equals Bebe heating. Do you group or the Divided by Bebe Do positive concentration multiplied with 2.5 10 days to put negative eight. Now solving this we have divided by the concentration off. Let it bother you equals school point Zeal 10 ways to ball waiting multiplied with to appoint flavor 10 days to power Negative Solving this We have the value of fight 10 days stupor waiting the concentration off the issue off the lead to positive in the blood Through the complex formation can be liberalised. We have one by five multiply 10 days to power them this upon solving we have a zero point toe, 10 days to power. Negative them. Therefore the ratio off free lead to positive. So the complex formation is zero point toe 10 raise to power negative.

Keenan Mintz · Answer

So now we&#x27;ll work on problem 49 from Chapter eight and this problem. We&#x27;re told about mercury ions, how they can be removed from solution by precipitating with chlorine chloride. And so, if you have a solution, which has this mercury nitrate, we want to write the complete in that attic equations to show how this insoluble mercury chloride is formed by mixing with sodium nitrate, sodium chlorate. So first, let&#x27;s draw a complete reaction. We&#x27;re mixing two solutions of mercury nitrate and sodium chloride, so this mercury, uh, compound is a weird cata, and it&#x27;s HD, too, and it has a two plus charge, so we need tohave to nitrate ions. So this is aqua yous and of course, so in chloride is aqua yous. But we&#x27;re producing a mercury chloride H G to see out to which is a solid, and we&#x27;re also producing sodium nitrate, which is, of course, soil and aqua yous. So to balance here, we need to add, um, 2 to 7 chlorine so we could have two Corinne&#x27;s on both sides and then too, to the sodium nitrate so we can balance the sodium and the night train. So this is our chemical equation here. They want us to a complete and net ionic equations. So to write our complete ionic equation, we need to disassociate are reacting. It&#x27;s because they&#x27;re all Aquila&#x27;s. So we have this mercury eye on it. She 22 plus, which is Aquarius. We have our two nitrate in ions, which are both Aquarius. We have to sodium, which are obvious and to chlorine. We propagate the cool, striking metric coefficient throughout the compound for this sort of clarity. Um, and then on the right, um, we have our solid, which we don&#x27;t want to, uh, ionized because it will not associate in solution. It seizes a solid. And then we have our to city in pluses in our to n 03 minus both awkwardness. So now we just need to cancel what doesn&#x27;t change. And ray, what remains for Annette had equation. So our nitrate in our sodium doesn&#x27;t change across the reaction so we can write the re equation as mercury to two plus, which is Aquarius. Plus, there were two chlorine in ions and this produces this mercury chloride ionic compound

Susan Hallstrom · Answer

Okay, prepare yourself. This one&#x27;s gonna take forever. That&#x27;s a giant problem. And in this giant problem were given some data. I&#x27;ll talk about this as we go, we&#x27;re gonna plot the data, make a graph, and what we&#x27;re gonna end up plotting will be the natural law. Guepy versus one over Kelvin temperature. We&#x27;re going to find the temp given different vapor pressures. And we&#x27;ll do that by looking at the graph and will do at least one calculation so you can see how they compare. We&#x27;re going to find the normal boiling point. What&#x27;s not the normal plaint? What the heck is a normal point? A normal boiling point. And we&#x27;re gonna find the MP of vaporization. Okay, let&#x27;s begin. Okay, let&#x27;s really begin. So I made a little graph here. It&#x27;s not perfect, and this is not easy for me to write, but I&#x27;ll do the best I can. So for the information that were given were given temperature in C degrees, we&#x27;re gonna have to convert that to Kelvin and then after we have Kelvin will find one over Kelvin. We are also given pressure, and when we have pressure, then we&#x27;re going to find the natural lot. So let me see if I can make some lines here that are moderately straight and I cant so this will tell you just how bad it&#x27;s going to be when I have to draw the line for our graph. Okay, So are given. Temperatures all in Celsius are as follows 14. 53.8, 84.3 one of 8.3 and 1 51.4 Okay, for each of these, add to 73 I just went plain old to 73 and then I once I have this number, if you&#x27;re doing the calculations, once I have this number, then I just press extra the minus one get 00 3484 That&#x27;s a zero. Okay. And then after that, I&#x27;m going to write the rest down, because it&#x27;s just a little quicker. These are my temperatures, right? Right. That incorrectly. 3 50 7.3 3 81.3 and 4 24.4 Okay. And then one over. Que For each one of these, these are all going to be 00 point. I&#x27;m gonna write this in first, and then I get for this 130600 27988 26 2 to 6, 2356 Okay, so far, so good. Then we&#x27;ve got 1 10 40 104 100 for my vapor pressures. When take natural logs, I get zero 2.30 And I&#x27;m just going to use you&#x27;ll know when I get to the graphs that I mean around these to the nearest 10th. Okay, very good. Now we are going to graph this column and this common and you can see from my graph right here, which go that my temperature, my one over temperature goes on the x axis and the vapour pressure goes on the white. Okay, I&#x27;m gonna mark my spots with an X here as best I can. And forgive me because I&#x27;m not the greatest artist. And my lines are here, Here, here and here. Okay, so I&#x27;m going to do zero and 34 84 which is going to be almost to the 35 right there. There&#x27;s that data point. I&#x27;m working with the necks next. I&#x27;m gonna dio Actually, I might make this a little bit bigger here. I can right now without messing up too much. I&#x27;ll have to move my access. But this will be a little easier for us to read. There we go. Get it as big as we could get it. There we go. And I should have erased these two because now they look silly. Okay? Again, we&#x27;re going to go at our three point almost 3.5 and zero right there. My next point is going to be 2.3 and 0.30 Look, so right up here, 2.0, 2.3 and 3.0. Dang it. I&#x27;m having trouble with this. Now there goes that and 2.3 3.0. Okay, whatever it is that&#x27;s gonna be good than 3.69 We&#x27;re gonna take for 3.7 right around and there and point to a dish. So there&#x27;s 5678 That&#x27;s 3.7 right about there. And my next point is 4.6 and 26 26. So it&#x27;s gonna be right on this side. 4.6. Okay. And my last point is gonna be about six ish and 23 56. So that will be right in there and right about there. Okay, well, that looks pretty straight, considering that this is really hard for me to dio. I don&#x27;t think I can hold a straight at John here. I&#x27;m gonna try to do this in Green, and I&#x27;m gonna try to just sort of, like, hold my phone up here and see if I can try this and draw a line. I wouldn&#x27;t bet on it, but okay, definitely not a great line, but it&#x27;s good enough for the work that we&#x27;re going to do right here. If you were going to put this into a calculator, something would be better. But I just don&#x27;t have that ability right now. Okay? Now, we&#x27;re also given 250 millimeters of mercury and were given 6 50 millimeters of mercury, and later on, we&#x27;re going to be considering one atmosphere 7 60 millimeters of mercury. So right now, we&#x27;re going to look at these. We&#x27;re gonna take the natural log of each one of these, and then we&#x27;re going to look up the graph and figure out what our, um, temperatures from the graph. So the Ln of 2 50 is 5.5. I&#x27;m just going to go to to say things because that&#x27;s by far the easiest. So we&#x27;re right there and that when I look at that, that looks like it&#x27;s almost exactly at 0.25 So if I take the this, if I take this the reciprocal of that. So I&#x27;m going to do 0.25 extra the minus one enter. I get 400 k Now, if a subtract 2 73 from that, that equals 127 degrees C and we&#x27;ll come back and compare these. Okay, Now we&#x27;re going to the same thing for the 6 50 We&#x27;re gonna take the natural August 6 50 which is, um, 6.5. We&#x27;re gonna look at 6.5 up here, and that looks like it&#x27;s at 0.0 to 2. And when I do my 00 to 2 extra minus one, I get 4 54 Kelvin and minus 2 73 I get 1 81.5 but I&#x27;ll go 1 81 close enough for us for what we&#x27;re doing right here and then last but not least, um and I haven&#x27;t tried this one, so we&#x27;ll see if it works here. I&#x27;m gonna take the negative longest 7 60 Yes, it will. And I get what&#x27;s not the negative lock. A natural log of 7 60 and I get 6.63 So a little bit above here, like maybe right in there. So I&#x27;m looking at maybe 0.0 to 15 So let&#x27;s 00 to 15 and I&#x27;m gonna take the negative log of that. And I get 4 65 minus 2 73 and gives me 1 92 So we&#x27;ll come back and compare these values that we looked at on the let me erase. Couple things here will come back and look at these values after we&#x27;ve calculated to see how they compare. Okay, Now we&#x27;re going to use this calculation right here. First, we&#x27;re gonna find Delta H. Then we&#x27;re gonna find tea for 2 50 millimeters mercury like we did in the last page. 6 50 and 7 60 And that will bring us to the end. Let me make sure my camera is still on it. ISS Okay, so the first thing we&#x27;re gonna do is our Delta H. Let&#x27;s go to a little darker color lips next page again. So we&#x27;re going to do the l N of. And I chose to use the 400 millimeters mercury and the 10 millimeters of mercury, which, of course, will cross out. And that&#x27;s gonna equal the negative heat of vaporization over. And my are I&#x27;ve adjusted for killer jewels. And then that&#x27;s came all I&#x27;ve got one over my Kelvin temperature for 24.55 minus 1/3. 26.95. Okay, let me see. That&#x27;s everything. So I&#x27;ll do a little bit more work with this one, and then you&#x27;ll be able to figure it out much easier. 6889 equals my heat negative heat of I&#x27;m just gonna go heat this time. And that will be killed, Jules per que times mall. And then this term is going to reduce to negative seven point 037 08 times 10 to the minus fourth Que to the minus one. You&#x27;re right. I did. And that will give me as you&#x27;ll see killer jewels per mole. So now it&#x27;s pretty easy. I&#x27;m gonna multiply both sides by, um, this is a then divide by that. So I&#x27;m going to get my delta heat of vaporization. When I saw for the rest of this, I got 43 0.6 lips, 43.6 killer jewels per mole. And I looked it up. What the true value is and this is a little off, but I don&#x27;t know if it&#x27;s a little life, because I did a little air somewhere, So you&#x27;re welcome to look for that. Okay, so there&#x27;s my heat of vaporization. That&#x27;s my delta heat of vaporization. And I&#x27;m gonna use this 43.6 in the next three problems. So I&#x27;m going to use the same problem now. And this time, remember, to 50 was one of our 2 50 millimeters of mercury, which again will cross out. And I just opted to use 10. Um and that&#x27;s gonna equal our we calculated Negative. We calculated 43.6 killer jewels. This is 0.83145 times one over X. This is what we&#x27;re solving for minus one over 3 26.90 Oh, I see. I would use 95 there, so I used, um, 273.15 right here. Okay, so this reduces to 3.2189 equals a negative. This value is 5200 43.9. And this is going to be this right here. We have killer jewels per came all. So this is going to be K Times Bowl, because I would come to the numerator, and then I&#x27;ve still got my one over X minus 0.0 30 I knew this was gonna happen. I should&#x27;ve wrote a little smaller. I&#x27;m not starting this over. So you&#x27;re stuck with this? So right here, I have five negative five to for 3.9 came all in one over X minus 0.305 86 Que to the minus one. Okay, so I think you&#x27;ll Well, well, well. Just keep going here. We&#x27;re looking for Kate, as I&#x27;m sure you can see. So now, when I divide this value by this, I don&#x27;t even know where I am. I get 0.0. No, not yet. I don&#x27;t. For this one problem, I&#x27;ll do a little extra. So when I divide this number by this number. I get negative 6.1384 times 10 to the minus fourth equals one over X minus 0.30 five 86 Now I add this term to each side and I get 0.2445 equals one over X. So when I take the reciprocal of that, I get 409 que subtract 2 73 equals 1 36 degrees Celsius. So let&#x27;s go back and see. So we got 1 25 from my very poorly written graph, so we weren&#x27;t too far off there. You can see I wasn&#x27;t straight It all here. You know, My whole thing should have shifted a little bit, But you can see that. Okay, Now let&#x27;s do one more. We&#x27;re going to the exact same calculation. I&#x27;ll switch colors, but this time we&#x27;re going to use 6 50 and 10 and I&#x27;m just gonna go ahead and put my negative five to 43.9 and one over X minus. It&#x27;s gonna be the same value here because I made sure to use the same number 0.0 30586 That&#x27;s Kate of the minus one, and we&#x27;re looking for Kay&#x27;s here. So for this one, take your natural log rhythms of this number. I&#x27;m not gonna write nearly as much down here. I get one over X equals four equals zero point 00 to 262 That&#x27;s the value I get. So X equals. The reciprocal of that is 442 Kelvin, Subtract 2 73 and I got 1 69 degrees Celsius again. Let&#x27;s go back and see what we got here. Who I was a little further off, but yet it might line should have been steeper, so it would have been a little higher. And we have one more and I have to go to the next page. But this is the same thing, and it&#x27;s just going to be my Ln this time of 7 60 over 10 equals negative, and we&#x27;re doing the same thing here. 3 26 No, no. Five 243.9 one over X minus 0.0 30586 Very good. And right now I&#x27;m looking to see where I wrote this one down. Okay. When all was said and done here, I got one over X equals 0.0 to to 2 to 3, 27 So x equals. Take the reciprocal of that. I got 4 48 Subtract 2 73 for 1 75 degrees degrees Celsius. I&#x27;m pretty sure that&#x27;s it. And my computer, with the problem on its shut off because this took so long, so that&#x27;s gonna have to be it.

Kim Trang Nguyen · Answer

got a question. 1 59 We can show the problem by this a. A wide that road reaction stop because the Qassam so fake when that councils will faII form produce, it will cover the surface off the calcium NATO so they revenge Castle Meadow from continue. React with the acid. Like what? The reaction stop and why I love me Numb appeared to be under reacted towards thing when hydro love it because I only know because aluminum react with office procedure in the a m do farm aluminum oxide. Anel Amina&#x27;s I does not react with water esteem and hydro love it such. It&#x27;s the only Alona inside can react with the asked us is the solution I don&#x27;t love with passive, not the steam See sodium and potassium Dona React Do not cover. I am two plus the metal couple because in the water column, so you both assume react with the water before reacting. A couple. I am Larry acid like the reaction like this, and may they mento m react. Being slowly. This mean it&#x27;s so it must than a bird. The hydrogen in a series of activity Siri up Meddoff dignity, but it cannot react with. I do so fight. That&#x27;s mean this medal that the reduction is this metal is tradition, agent much quicker than I am a stronger than hydrogen It&#x27;s must and before hydrogen it&#x27;s must be doing hydrogen and I e that question asked with metal can reduce aluminum Laura So that&#x27;s metal Have to spend over a lot, you know? And that&#x27;s metal Cannery quit No water Why? You seen okay in C question Okay, Because it that metal react quicker water they cannot produce It does not reduce aluminum a produce aluminum hydroxide so Onley magnesium can reduce aluminum Hamas from aluminum aluminum Lawry if you let lady on Barhoom now psyllium Qassam what are some reequip floor? I it will convert aluminum chloride to aluminium hydroxide and we see aluminum is not reduced. And if you want the new aluminium hydroxide, most be the combo in the high aluminum outside so we can electron as it alumni outside the rodeo&#x27;s

Himanshu Garg · Answer

in this problem, we had to explain the reason as to why the particular chemical phenomena happens in some, but a The solution is that the precipitate calcium sulfate forms over calcium metal and prevents the calcium from reacting. But the sulphuric acid in support be. The solution is that the aluminium is protected by a tenacious oxide layer on the surface with a composition ale toe. Three are aluminum oxide in support. See. The reason is that the petition and sodium reacts more readily with border. The equation representing that is given here and therefore they don&#x27;t displays copper iron from copper sulfate solution in somebody. The solution is that the metal reacts slowly with hydrogen. Therefore, it should be above hydrogen. However, it doesn&#x27;t displace Ireland from iron sulfate solution, and therefore it should be below Ireland in the reactivity table. Therefore, this unknown metal should be between hydrogen and iron in support. Either solution is that, and in metal above aluminum in the activity cities will react with aluminium. I&#x27;m metals from magnesium to lead him will work in this case

Problem

Describe at least three types of effects that a t…

Problem 5 Easy Difficulty

Answer

a) olid mercury chloride is added to a solution of EDTA to produce a solution containing a compound of mercury with EDTA and hydrochloric acid.
olid mercury chloride is added to a solution of EDTA to produce a solution containing a compound of mercury with EDTA and hydrochloric acid.

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a) olid mercury chloride is added to a solution of EDTA to produce a solution containing a compound of mercury with EDTA and hydrochloric acid.olid mercury chloride is added to a solution of EDTA to produce a solution containing a compound of mercury with EDTA and hydrochloric acid.

Living by Chemistry

Stephen P.

Allea C.

Morgan S.

Jake R.

Intro To Chem - Introduction

Classification and Properties of Matter

Angelica M. StacyLiving by Chemistry

Stephen P.

Allea C.

Morgan S.

Jake R.

a) olid mercury chloride is added to a solution of EDTA to produce a solution containing a compound of mercury with EDTA and hydrochloric acid.
olid mercury chloride is added to a solution of EDTA to produce a solution containing a compound of mercury with EDTA and hydrochloric acid.

Angelica M. Stacy

Living by Chemistry