Question
Polar Form of Complex Numbers Write the complex number in polar form with argument $\theta$ between 0 and $2 \pi$.$$1-i$$
Step 1
The modulus is given by the formula $r=\sqrt{a^2+b^2}$, where $a$ and $b$ are the real and imaginary parts of the complex number respectively. In this case, $a=1$ and $b=-1$. So, we have $r=\sqrt{1^2+(-1)^2}=\sqrt{2}$. Show more…
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