The modulus is given by \(R = \sqrt{a^2 + b^2}\), where \(a\) and \(b\) are the real and imaginary parts of the complex number respectively. In this case, \(a = -3\) and \(b = 3\). So, we have \(R = \sqrt{(-3)^2 + 3^2} = \sqrt{9 + 9} = \sqrt{18}\). We can simplify
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