00:01
In this problem, we're given a population of rabbits with the initial population b0 of 100, and the growth rate is exponential with a rate of 11 .7 % per day.
00:20
So let's convert the percentage into decimal, and we can do that by dividing by 100, and we get 0 .117 as r.
00:32
Now the standard form for an exponentially growing population is given by the formula b of t, which is population at any given time equals p .0 times e to the rt.
00:50
Now p0 is just 100, so the initial population, and it's raised to the power e of rt, and r is 0 .117.
01:02
So our population function as a function of time equals, p of t equals 100 times e to the 0 .117t.
01:18
Now for the second part, we need to graph this function.
01:27
So we need to make a rough sketch of the function.
01:41
So we can have our horizontal axis of t and our vertical axis as p of t.
01:54
So it starts at 100.
02:03
So from here we can calculate a few values.
02:07
And a few useful ones will be the multiple times.
02:13
Of 5, so pf 0 is just the initial population, which is 100.
02:20
So we'll plot that point.
02:24
P of 5 is equal to 100 times e to the 0 .117 times 5, which equals 179.
02:36
We can round that off as 180, and we can plot that point somewhere over here.
02:44
Now we can do the same thing to find pf 10.
02:47
So b of 10 equals 100 times e to the 0 .117 times 10.
02:56
And that equals 32 .19.
03:02
So we can plot that point somewhere over here...