00:01
Okay, so we're doing a new problem here, problem 25, and we are given an acceleration.
00:10
We have at zero seconds, the velocity is 70, and at zero seconds, the distance is 10.
00:15
So we are given the equation, the function that the acceleration in terms of time is negative 32, and we're going to figure out the velocity, we're going to figure out the velocity, the function of velocity, and the function of distance of the position.
00:32
So to do that, we're going to start with the velocity.
00:34
So we know that negative 32, we're going to find the anti -derivative, because the anti -derivative of the acceleration is the velocity.
00:42
So the antide derivative of negative 32 is t plus c.
00:48
We're adding the plus c because we have an unknown value that we need to figure out.
00:51
And we know that at time zero, the velocity is 70.
00:58
So, we know that v of 0 equals 70, so negative 32 times 0 plus c is equal to, this cancels, and c is equal to 70.
01:13
So, our equation for the velocity is v of t equals 70 minus 32t...