00:01
So here we have two parts of motion.
00:03
So to find the average velocity for part a, this would be equal to the change and displacement in the x direction with respect to time.
00:14
This would be equaling to delta x sub 1 plus delta x sub 2 for the two parts of motion divided by delta t sub 1 plus delta t sub 2.
00:25
So we can then say that for the first part of motion for part a, the displacement delta x of 1 is equaling 40 kilometers.
00:39
Now, the time taken would essentially be t sub 1 or delta t sub 1, and this would be equaling to 40 kilometers, and then we're traveling at 30 kilometers per hour.
00:55
So this is equaling 1 .33 hours.
00:59
And then we have delta t sub 2.
01:02
This would be equaling to 40 kilometers however now we're traveling at 60 kilometers per hour and so this is giving us 0 .67 hours and so we can say that then again for part a the average velocity is going to be equaling to again delta x divided by delta t so this would be equaling to 80 kilometers divided by two hours giving us 40 kilometers kilometers per hour.
01:40
So this would be our answer for part a.
01:43
For part b then, we know that in this case, the average speed is the same as the magnitude of the average velocity...