00:01
We're going to let vw be the velocity of the wind, and then we can say v -c would be the velocity of the car.
00:12
So we can say that first for part a, we can say that during the time interval t -1, they're going to be both moving in the same direction.
00:21
So we can say that the effective speed of the car essentially would be equal to the velocity of the car plus the velocity of the wind, because in this case, the wind is helping the car.
00:38
We can say that the distance traveled would then be d equaling the effective sub 1 times t sub 1, and this would simply be equal to v .c plus v sub w times t sub 1.
00:56
We can then say on the return trip, though, during time interval t sub 2, the car moves in the opposite direction of the wind.
01:05
And so here on the return trip, the effective velocity would be the velocity of the car minus the velocity of the wind.
01:14
Again, the distance traveled would be equal to the effective sub 2 times t sub 2.
01:22
And this would simply be equal to v .c minus v sub w times t sub 2.
01:29
And so we can rewrite the two expressions.
01:32
We can say that v subc plus v sub w would be equal to d over t sub 1.
01:39
And then we can say v subc minus v sub w would be equal to d over t sub 2.
01:46
And so we're going to then add the two equations.
01:49
The velocity of the wind then cancels out...