00:02
Okay, so we have a function of velocity in respect to time, which is equal to 9 minus t squared on the interval of 0 to 4.
00:10
And we have at 0, time equals 0, the distance is equal to negative 2.
00:15
So what we're going to start by is graphing.
00:20
So we're going to start at 9, and it's going to be 0 at 3 because 9 minus 3 squared would be equal to 0.
00:31
So we get a graph that looks something like that.
00:37
And then we're going to be finding our intervals.
00:39
So our interval is positive.
00:42
Our velocity is positive when it's between zero and three, when time is between zero and three.
00:49
And it's negative when time is between three and four.
00:56
Okay.
00:57
So what we're going to do next is we're going to figure out the antiderivative of this to find the distance.
01:02
So distance is t.
01:05
Remember that when you are finding the antiderivative of an exponent, you're going to add one to the exponent and divide by that number.
01:12
So for this one, it's nine to the time, nine times t to five of zero.
01:16
So we get nine times t...