00:01
In this question, we are looking at calculating the ground state energy of a positronium atom, or the ground state ionization energy of a positronium atom.
00:13
So i've begun by writing out boz energy equation here on the board.
00:18
And by looking at it, we can see that most of this equation is constants, like the e or epsilon naught, but some parts aren't.
00:30
So the bits that we need to know are the z, the charge of the nucleus, the mass, and the n.
00:37
So the charge of the nucleus in our case, we're going to say is 1, because we are treating the positron as if it is our nucleus.
00:48
So z is equal to 1, so we can rewrite the top of the equation as minus m .e to the 4.
00:54
And then on the bottom of the equation, we know that n is equal to 1 because we're in the ground state.
01:00
So we have 8 h -bar squared, epsilon -not squared.
01:06
Then the only thing that we need to work out in this equation that is not a constant is the mass.
01:12
And we need the mass of the combined system.
01:16
So we need to use the reduced mass, which is the effective inertial mass of our two particles rotating together.
01:24
So reduced mass mu is found by doing the first mass times by the second, divided by the first plus the second.
01:33
Now in our problem, we have a positron and an electron, and they have the same mass.
01:38
So we can rewrite this as m e squared over 2me...