00:01
In this problem, we are considering potassium acid thallate, which is often abbreviated chp.
00:09
This can be obtained in high purity, and it's used to determine concentrations of solutions of strong bases.
00:17
And strong bases react according to the following reaction.
00:48
The molar mass of khp is 204 .2 grams per mole.
01:07
The ka for the hp minus ion is 3 .1 times 10 to the minus 6.
01:29
For part a, we are asked to identify which indicator would be most appropriate.
01:51
And we begin with 0 .485 grams of khp.
02:04
And we end up with a final volume of about 100 milliliters.
02:15
Okay, let's begin.
02:18
So the first thing we're going to do is figure out the molarity of our khp.
02:23
So we have, let me switch colors here, the following calculation.
02:32
We have that many grams per that much volume.
02:40
And then we're going to use the molar mass to convert this to molarity.
02:50
And for this i got 0 .02392 molar, and we'll round that later if we need to.
03:03
That will be the molarity at the equivalence of point.
03:08
And the ph at the equivalence point is going to be determined by the following equation.
03:16
It'll be the reverse of the equation up there.
03:58
And i think i'll do this on the next page, so i have room.
04:31
There we go.
04:33
So let's go ahead and write our kb expression for this.
05:07
And we said that was 3 .1 times 10 to the minus 6th, which equals 3 .3.
05:18
Let me see, what does that equal? 3 .23.
05:22
I'm going to run out of room there.
05:29
Times 10 to the minus 9th.
05:35
Okay.
05:38
So then let's set our changes as follows.
05:47
My concentration of p...