00:01
Here we will be using the vsepr theory to determine the geometric shape of our given molecules.
00:06
So, for example, on our first one, carbon monoxide, we first calculate the number of valence electrons.
00:12
We see that there are 10.
00:14
And then looking at our lewis structure that we draw, we will look at the central atom and determine how many electron groups are surrounding it.
00:23
And so i chose carbon.
00:25
Oxygen also works.
00:27
It will have the same number.
00:28
And so there will be two surrounding electron groups here.
00:34
And so going over to your vsepr table, you'll see that this means that it is linear.
00:42
So let's go ahead and move on to our next one, sicl4.
00:48
And so calculating the total number of valence electrons and then drawing out the lewis structure, you can see here that there will be a total of four electron groups surrounding the central atom.
01:00
And there are no lone pairs, and so this means that it will be tetrahedral shape.
01:10
Okay, moving on to our next one, we have ph3, seeing that there are eight valence electrons, and then drawing out the lewis structure, we will have a total of four surrounding electron groups.
01:26
But this time, you have to notice that one of these is a lone pair.
01:31
And so going to your table, when one of them is a lone pair out of the four electron groups, this means that it will be trigonal pyramidal pyramidal.
01:50
Okay, let's go to our next one.
01:52
And this is one that will have to have an expanded octet.
01:57
And luckily, iodine fits this rule because it's in the period three or below.
02:03
And so it can have more than eight electrons...