00:01
So we are given the following reaction.
00:03
We have an organic compound that is being reacted with acetic acid and heat.
00:08
We're also given that this occurs with an e1 elimination reaction.
00:12
So we want to go ahead and predict what products we're going to get from this reaction.
00:16
And of course the first step we know for any e1 elimination reaction is that our leaving group is first going to leave.
00:24
So that would be our bromide alkali.
00:27
So that will leave.
00:30
And we're going to get the formation of a.
00:31
A carbocadion.
00:33
Here in our case it's going to be a tertiary carbocation.
00:37
And now we can go ahead and do our deprotonation with our acetic acid.
00:42
Cetic acid is a pretty weak base, but once we put a lot of heat into it, it's capable of deprotinating.
00:48
So let's say we're going to deprotonate this hydrogen here.
00:54
And so we have our acetic acid, great, which is going to come in now, deprotonate that, and the electrons of this hydrogen are going to get pushed.
01:05
Down here.
01:07
So that is going to give us the following product where we get this formation of this salcine.
01:17
Now we can also deprotonate at a different hydrogen as well.
01:23
So let's say since we have our carbocetion intermediate here, let's say we make that red here, deprotonate at this beta hydrogen...