00:01
Okay, this problem is asking us to predict the products with reactions with proponil chloride.
00:07
Okay, so the first reaction with proponial chloride is with lithium, i'll do this in blue, lithium, fennel, and two equivalents, copper, and an ether solvent.
00:21
So what i just drew right there, that is called a gilman reagent.
00:24
A gilman reagent is a not -estronucophile enough to add twice, so instead it adds my phenyl one time.
00:31
So if i were to have another gelman reagent, i might have something else in the parentheses, but for this problem, i add my fennel only one time.
00:39
That is because it is not strong enough to add twice.
00:43
Okay, so those connect carbon -carbon bonds.
00:46
Okay, next up, i have lithium -aluminum hydride.
00:51
So lithium -aluminum -hydride is a very strong reducing agent, and if i react that with my proponamyl chloride, i should reduce my carbonyl down into an alcohol.
01:00
So let's check what kind of alcohol this is.
01:04
We have the two hydrants attached to it.
01:06
So we just formed a primary alcohol.
01:09
The reason we know is primary is because the carbon in which it is attached to is only connected to one other carbon.
01:15
So that is why we formed a primary alcohol.
01:19
Okay, next up, we have the reaction with ch3mgbr.
01:26
Okay, with acid workout.
01:28
So, ch3mgbr, that is a very strong nucleophile.
01:31
In fact, it is called a grineered reagent.
01:33
A greenerid reagent reacting with my proponil chloride will result in the addition of a methyl group two times.
01:39
That is because greenered reagents are very strong nucleophiles, and my proponil chloride is a very strong electrophile.
01:45
So when i combine the two forces of those, i will result in the formation of a tertiary alcohol.
01:51
And that is because i added my methyl group two times to my carbonyl.
01:57
Okay, next up, i have the reaction with hydronium, a hydronium ion.
02:04
Okay, so hydronium ion, that will result in a reaction with my proponinochloride, and i will have a formation of a carboxylac acid.
02:14
Okay, so this is just a hydrolysis reaction.
02:17
Okay, i can also undergo a hydrolysis reaction with n -a -o -h or hydroxide, and that will result in the formation of carboxylate...