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Predict the products for the reactions given below. Be sure to balance each equation.a. $\mathrm{HF}(a q)+\mathrm{NaOH}(a q) \longrightarrow$b. $\mathrm{HCl}(a q)+\mathrm{Mg}(\mathrm{OH})_{2}(a q) \longrightarrow$c. $\mathrm{HF}(a q)+\mathrm{N} \mathrm{H}_{4} \mathrm{OH}(a q) \longrightarrow$d. $\mathrm{CH}_{3} \mathrm{COOH}(a q)+\mathrm{NaOH}(a q) \longrightarrow$e. $\mathrm{HNO}_{3}(a q)+\mathrm{Mg}(\mathrm{OH})_{2}(a q) \longrightarrow$f. $\mathrm{HNO}_{3}(a q)+\mathrm{NH}_{4} \mathrm{OH}(a q) \longrightarrow$g. $\mathrm{CH}_{3} \mathrm{COOH}(a q)+\mathrm{Mg}(\mathrm{OH})_{2}(a q) \longrightarrow$$\mathrm{h} . \mathrm{CH}_{3} \mathrm{COOH}(a q)+\mathrm{NH}_{4} \mathrm{OH}(a q) \longrightarrow$i. $\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{HNO}_{3}(a q) \longrightarrow$j. $\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{Mg}(\mathrm{OH})_{2}(a q) \longrightarrow$

Chemistry 101

Chapter 16

Acidic Toxins

Section 5

Neutralization Reactions

Intro to Chemistry

Atoms, Molecules and Ions

Carleton College

University of Maryland - University College

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in problem for predictive product and balance each off the following equation. So first days when hydrogen fluoride reacts with the sodium hydroxide so it will form sodium fluoride and h toe. So this is the product off reaction. A. In the reaction be and it is balanced equation in direction be when hydrogen chloride at sale reacts with the magnesium hydroxide so it will form magnesium chloride. That is mgl too, along with H two liquid. So on balancing this occasion, we get to excel. And now this is the balance equation for this reaction. In a reaction C when hydrogen fluoride reacts with the sword ammonium hydroxide that is energy for college. So it will form ammonium fluoride. That is energy for F, along with H 20 So this is again a balance A situation. So in the that is when ascetic acid ch three c double ohh reacts with the sodium hydroxide so it will form sodium hesitate, which is ch three c double o n e along with H tour liquid. So this is again balance situation. So in party when at Channel Three, that mean nitric acid reacts with the magnesium hydroxide, so it will form magnesium nitrate, that is M G N 03 twice and h toe on balancing. We get, uh, coefficient off to in a general three and two h two. So this is the balance equation now, in part F in part, off off the equation. So, in part of off the equation, that is the, uh when at Channel three reacts with the ammonium hydroxide ammonium hydroxide, that is energy four or age. So it will form ammonium nitrate, NH four and no. Three and water and water. So and this is again a balanced equation. This is again balanced equation now in part G that when ascetic acid reacts with the magnesium hydroxide So this is the ascetic acid. When it reacts with the magnesium hydroxide, that is M g o H toys. So it will form magnesium as it did that is M g ch three c double o twice less XTO plus edge toe. So on balancing we get here, we get to as it stock American vision is to, and this is to which tour. So this is the balance situation now in part edge, when ascetic acid reacts with the ammonium hydroxide. So when ascetic as it wrecks with the ammonium hydroxide NH four h So it will form. In this case, ammonium as it did that is ch three c double o ch. Three c double o NH four and H two. So this is again a balanced equation. Now, in part, I off the equation is when h two s 04 react with the channel three. So So it will form h s or four minus equals less and no two positive equals and h 30 positive backwards. So on balancing we get so we get this equation. So this is the balanced situation? No, in the part G. So when sulfuric acid that is h two s 04 Uh, this as it reacts with the magnesium hydroxide m g o h twice. So it will form magnesium self with that is MGs off four and h 20 So this is the balanced equation for this case. So So these are the balanced equation, so I box in green color the answers. Now these are the answers. So these are the in the right hand side, this show our products and in the left hand side, these are the reactant. So we find the products as well as we balance the equations. So these are over answers. Let me highlight so that this is our answer for this. These occasions can understand better for these equations like this.

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