00:01
In this question, we are going to predict the product of products formed in the following reactions.
00:07
So let's look at the first reaction and look at the movement of electrons.
00:15
So here you can see a bond is formed between this carbon and this oxygen.
00:26
So let's represent that.
00:31
So we have c2 -1 -0, c -div -1 -0, carbon dioxide.
00:42
And the other product will draw out, the structure of it.
01:37
Okay, so here now there will be a double bond between carbon from the ring.
01:57
This carbon has a hydroxyl group and it also has a metal group.
02:15
So here you can see the double bond is formed between these two carbons here and a double one is broken between the carbon and the nitrogen.
02:28
So for the first reaction, these are the collocks formed.
02:35
So now let's look at the second reaction.
02:43
So for the second reaction, this carbon, oxygen brown is broken and the electrons move towards the oxygen in this quospeed group.
02:57
So let's represent that.
03:05
So we have this phosphate ion, negative charge here, p -03, 2 -1, this side.
03:20
Also you can see bond is formed between this oxygen and this carbon and this one is broken.
03:35
So that represents a second product.
03:41
So we have the ore, bonded to the oxygen.
04:07
So that takes care of this portion of the reaction...