0:00
Hello everyone.
00:01
Let us see the following question.
00:03
So here is a question where there are sequence of reagents given.
00:08
So we have to find out the last product.
00:10
So the mechanism we will have to directly go through.
00:16
So we'll see we have a cyclopentanone, okay, which is substituted with side chain alcohol.
00:27
First it has to be treated with ethylin glycol.
00:30
How do we write ethylaryl? ch2 2 times oh2 group on both the sides, okay? followed with hydrolysis.
00:40
Then it is further treated with colin's reagent, colin's reagent, which is a weak oxidizing agent, which is then further treated with ethyl, c2h5, mg, br, and then further hydrolysis, h plus and h2o we have to tell the final product in the sequence.
01:07
So let us go to the mechanism.
01:13
So in the mechanism i'm having cyclopentinone.
01:19
So there is double bond o and then there is oh.
01:24
When treated with the ethylene glycol, see ethyline glycol i'm going to write like this.
01:29
Ch2, ch2, oh and oh.
01:39
We have to remove one unit of water here.
01:42
So as we remove one unit of water here, this is going to condense.
01:47
So, basically, i am going to protect one of the ketone group.
01:51
Okay, see what we are going to do here.
01:54
So, this is going to be connected to oxygen, oxygen, ch2, ch2.
02:01
So, we got cyclic acetyl.
02:08
Cyclic, not acetyl, we can say that ketal because anyway this is going to be cyclical.
02:16
Okay, so now further i am going to treat it with colin's reagent, cr.
02:21
With the colin's reagent, since it is weak oxidizing agent, it is going to oxidize this primary alcohol to respective rdehyde.
02:30
So, i am still protecting that oxygen over here...